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called function A(args) calls a function B() which then calls a function A(args), How to do that?

Answer 1

+1 A:

You need to pass the caller and arguments to load_api, otherwise how could it know the values of the irrelevant variables?

        function load_api(f, text) {
         ...

        function detect_language(text) {
            if (!loaded) {
                load_api(detect_language, text);  // or use load_api(arguments.callee, text)

And then you can invoke those in the callback.

                "callback": function() {
                    loaded = true;
                    f(text);

If A is variadic, you can use the arguments variable and Function.apply:

function A (x, y, z) {
  B(A, arguments); // or B(A, [x, y, z])
}
function B (f, arr) {
  setTimeout(1000, function() {
    f.apply(this, arr);
  });
}

KennyTM 2010-03-20 15:53:02

thanks for a solution. How to be if functions/callers have different number of agruments?

Ken 2010-03-20 15:58:26

@Ken: See update.

KennyTM 2010-03-20 16:12:13

Answer 2

+1 A:

If you call google.load more than once, it is smart enough not to include the script again, but your callback will still get called. Thus, you can just do:

function load_api(callback) {

    google.load("language", "1", {
        "nocss": true,
        "callback": callback
    });
}

function detect_language(text) {
    load_api(function() {
        // let's continue... believe that google.language is loaded & ready to use
        google.language.detect(text, function(result) {
            if (!result.error && result.language) {
                document.getElementById('language').innerHTML = result.language;
            }
        });
    });
}

function translate(text) {
        load_api(function()
        {
          // Do whatever you want, including using text.
        });
}

Note that because of the way closures work, you can freely use the function arguments in your callback. But you may find it simpler to just have a single callback at page load, and hide any translation controls until the callback completes.

Matthew Flaschen 2010-03-20 16:01:30

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called function A(args) calls a function B() which then calls a function A(args), How to do that?

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