Hi,
does somebody knows how to check for a valid IMEI?
I have found a function to check on this page: http://www.dotnetfunda.com/articles/article597-imeivalidator-in-vbnet-.aspx
But it returns false for valid IMEI's (f.e. 352972024585360). I can validate them online on this page: http://www.numberingplans.com/?page=analysis&sub=imeinr
What is the correct way(in VB.Net) to check if a given IMEI is valid?
Regards, Tim
PS: This function from above page must be incorrect in some way:
Public Shared Function isImeiValid(ByVal IMEI As String) As Boolean
Dim cnt As Integer = 0
Dim nw As String = String.Empty
Try
For Each c As Char In IMEI
cnt += 1
If cnt Mod 2 <> 0 Then
nw += c
Else
Dim d As Integer = Integer.Parse(c) * 2 ' Every Second Digit has to be Doubled
nw += d.ToString() ' Genegrated a new number with doubled digits
End If
Next
Dim tot As Integer = 0
For Each ch As Char In nw.Remove(nw.Length - 1, 1)
tot += Integer.Parse(ch) ' Adding all digits together
Next
Dim chDigit As Integer = 10 - (tot Mod 10) ' Finding the Check Digit my Finding the Remainder of the sum and subtracting it from 10
If chDigit = Integer.Parse(IMEI(IMEI.Length - 1)) Then ' Checking the Check Digit with the last digit of the Given IMEI code
Return True
Else
Return False
End If
Catch ex As Exception
Return False
End Try
End Function
EDIT: by the way, this is my "checkIMEI"-Function:
Public Shared Function checkIMEI(ByRef IMEI As String) As Boolean
Const allowed As String = "0123456789"
Dim cleanNumber As New System.Text.StringBuilder
For i As Int32 = 0 To IMEI.Length - 1
If (allowed.IndexOf(IMEI.Substring(i, 1)) >= 0) Then
cleanNumber.Append(IMEI.Substring(i, 1))
End If
Next
If cleanNumber.Length <> 15 Then
Return False
Else
IMEI = cleanNumber.ToString
End If
For i As Int32 = cleanNumber.Length + 1 To 16
cleanNumber.Insert(0, "0")
Next
Dim multiplier As Int32, digit As Int32, sum As Int32, total As Int32 = 0
Dim number As String = cleanNumber.ToString()
For i As Int32 = 1 To 16
multiplier = 1 + (i Mod 2)
digit = Int32.Parse(number.Substring(i - 1, 1))
sum = digit * multiplier
If (sum > 9) Then
sum -= 9
End If
total += sum
Next
Return (total Mod 10 = 0)
End Function