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635

answers:

5

Not sure this is possible, but Looking to write a script that would return the average hex or rgb value for an image. I know it can be done in AS but looking to do it in JavaScript.

+3  A: 

Javascript does not have access to an image's individual pixel color data. At least, not maybe until html5 ... at which point it stands to reason that you'll be able to draw an image to a canvas, and then inspect the canvas (maybe, I've never done it myself).

Joel Martinez
+5  A: 

I would say via the HTML canvas tag.

You can find here a post by @Georg talking about a small code by the Opera dev :

// Get the CanvasPixelArray from the given coordinates and dimensions.
var imgd = context.getImageData(x, y, width, height);
var pix = imgd.data;

// Loop over each pixel and invert the color.
for (var i = 0, n = pix.length; i < n; i += 4) {
    pix[i  ] = 255 - pix[i  ]; // red
    pix[i+1] = 255 - pix[i+1]; // green
    pix[i+2] = 255 - pix[i+2]; // blue
    // i+3 is alpha (the fourth element)
}

// Draw the ImageData at the given (x,y) coordinates.
context.putImageData(imgd, x, y);

This invert the image by using the R, G and B value of each pixel. You could easily store the RGB values, then round up the Red, Green and Blue arrays, and finally converting them back into an HEX code.

rnaud
any chance there is a IE alternative to the canvas solution?
Ben4Himv
@Ben4Himv: There's the IE9 Platform Preview ;-) but seriously, I'm afraid not.
Andy E
+5  A: 

AFAIK, the only way to do this is with <canvas/>...

DEMO: http://jsfiddle.net/xLF38/

Note, this will only work with images on the same domain and in browsers that support HTML5 canvas:

function getAverageRGB(imgEl) {

    var blockSize = 5, // only visit every 5 pixels
        defaultRGB = {r:0,g:0,b:0}, // for non-supporting envs
        canvas = document.createElement('canvas'),
        context = canvas.getContext && canvas.getContext('2d'),
        data, width, height,
        i = -4,
        length,
        rgb = {r:0,g:0,b:0},
        count = 0;

    if (!context) {
        return defaultRGB;
    }

    height = canvas.height = imgEl.naturalHeight || imgEl.offsetHeight || imgEl.height;
    width = canvas.width = imgEl.naturalWidth || imgEl.offsetWidth || imgEl.width;

    context.drawImage(imgEl, 0, 0);

    try {
        data = context.getImageData(0, 0, width, height);
    } catch(e) {
        /* security error, img on diff domain */
        return defaultRGB;
    }

    length = data.data.length;

    while ( (i += blockSize * 4) < length ) {
        ++count;
        rgb.r += data.data[i];
        rgb.g += data.data[i+1];
        rgb.b += data.data[i+2];
    }

    // ~~ used to floor values
    rgb.r = ~~(rgb.r/count);
    rgb.g = ~~(rgb.g/count);
    rgb.b = ~~(rgb.b/count);

    return rgb;

}

For IE, check out excanvas.

J-P
Is there any way to get the color histogram for an image lying on a different domain?
Dan Loewenherz
+1  A: 

First: it can be done without HTML5 Canvas or SVG.
Actually, someone just managed to generate client-side PNG files using JavaScript, without canvas or SVG, using the data URI scheme.

Second: you might actually not need Canvas, SVG or any of the above at all.
If you only need to process images on the client side, without modifying them, all this is not needed.

You can get the source address from the img tag on the page, make an XHR request for it - it will most probably come from the browser cache - and process it as a byte stream from Javascript.
You will need a good understanding of the image format. (The above generator is partially based on libpng sources and might provide a good starting point.)

andras
Awesome answer.
Plynx
+7  A: 

"Dominant Color" is tricky. What you want to do is compare the distance between each pixel and every other pixel in color space (Euclidean Distance), and then find the pixel whose color is closest to every other color. That pixel is the dominant color. The average color will usually be mud.

I wish I had MathML in here to show you Euclidean Distance. Google it.

I have accomplished the above execution in RGB color space using PHP/GD here: https://gist.github.com/cf23f8bddb307ad4abd8

This however is very computationally expensive. It will crash your system on large images, and will definitely crash your browser if you try it in the client. I have been working on refactoring my execution to: - store results in a lookup table for future use in the iteration over each pixel. - to divide large images into grids of 20px 20px for localized dominance. - to use the euclidean distance between x1y1 and x1y2 to figure out the distance between x1y1 and x1y3.

Please let me know if you make progress on this front. I would be happy to see it. I will do the same.

Canvas is definitely the best way to do this in the client. SVG is not, SVG is vector based. After I get the execution down, the next thing I want to do is get this running in the canvas (maybe with a webworker for each pixel's overall distance calculation).

Another thing to think about is that RGB is not a good color space for doing this in, because the euclidean distance between colors in RGB space is not very close to the visual distance. A better color space for doing this might be LUV, but I have not found a good library for this, or any algorythims for converting RGB to LUV.

An entirely different approach would be to sort your colors in a rainbow, and build a histogram with tolerance to account for varying shades of a color. I have not tried this, because sorting colors in a rainbow is hard, and so are color histograms. I might try this next. Again, let me know if you make any progress here.

Boaz
This is one of those answers for which I wish I could do more than just +1 :-)
David Johnstone
Excellent answer even though a clear solution wasn't rendered. This will help me decided my next step...
Ben4Himv