I want a regular expression for only accepting 0-9999
No spaces, no letters. However, "blank"(empty) is allowed.
+8
A:
\d?\d?\d?\d?
Should do it.
Or more succinctly:
\d{0, 4}
This works because you're saying "0, 1, 2, or 3 digits", where each digit is 0-9. This allows numbers between 0 and 9999, and nothing else.
Note that it allows leading zeros, i.e. 0004 is a valid number.
Eli Bendersky
2010-03-30 12:22:31
Seems to allow a space
Coolcoder
2010-03-30 12:54:16
@Coolcoder: do you restrict it to be the whole string (i.e. with start string and end string symbols)?
Eli Bendersky
2010-03-30 13:08:51
No spaces, period. Not at start, not at end , not in the middle. Just a space on its own is also not allowed. However, "blank" (no value) is ok :)
Coolcoder
2010-03-30 13:20:54
@Coolcoder, in case my previous comment wasn't clear: `^\d{0,4}$`: restricting the string to be **only** the digits, not just containing them
Eli Bendersky
2010-03-30 13:23:25
+7
A:
well, /\d{0,4}/ is the simplest way, but generally I convert to a number and then do bounds checking
Gareth
2010-03-30 12:23:58
+4
A:
Assuming you don't want to accept numbers left-padded with zeros.
(0|([1-9]\d{0,3}))?
Read as zero or one of the following: 0 or a 1-9 followed by a 0 to 3 digit string.
tvanfosson
2010-03-30 12:29:15
Shouldn't match a space at all since there is no whitespace anywhere in the expression. Depending on how you are using it you may need to add matching characters for the start and end of string: `^(0|([1-9]\d{0,3}))?$`
tvanfosson
2010-03-30 13:54:18