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RSA PKCS1 implementation in Python

I'm working on the RSA PKCS1 implementation in Python,here's the message block i got:

m = [0,2,random paddings,0,message integers]

I read the RFC2313,and get a equation seems for transforming the message block object into an big-edian integer. I just get confused about how to transform it in Python.

Any help would be appreciated.

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