views:

393

answers:

9

I want to run a console application (eg app.exe) from a windows form load event. I'v tried System.Diagnostics.Process.Start(), But after it opens app.exe, it closes it immidiately.

Is there any way that I can run app.exe and leave it open?

+1  A: 

Console application always closes just after it finished its work. If you need to have some app running all the time then you maybe need a service, not console application.

Andrew Bezzub
+1  A: 

If you can change the code of app.exe, just add Console.In.Read() to make it wait for a key press.

Matthew Ferreira
+2  A: 

If app.exe does nothing, or finishes its work quickly (i.e. simply prints "Hello World" and returns), it will behave the way you just explained. If you want app.exe to stay open after its work is done, put some sort of completion message followed by Console.ReadKey(); in the console application.

Pwninstein
+1  A: 

app.exe can end with Console.ReadLine() assuming it too is a C# application where you control the source code.

Austin Salonen
A: 

You have one of two problems, given your master/slave application setup:

  1. Your master app is opening, displaying a form, that form runs the slave app and closes immediately, even though the slave app is still running.
  2. Your master app is opening, displaying a form, that form runs the slave app which closes immediately.

For the first problem, you need to wait/block for the process to complete (i.e. Process.WaitForExit().

For the second problem, it sounds like the slave app has done what it needs to (or thrown an exception) and is closing immediately. Try running it with the same parameters from a command prompt and check the output.

Neil Barnwell
+4  A: 

If you are just wanting the console window to stay open, you could run it with something like this command:

System.Diagnostics.Process.Start( @"cmd.exe", @"/k c:\path\my.exe" );
Mark Wilkins
Works, but my path is from a textBox, so if I have space in my path it wont work
Or Betzalel
@Or Betzalel: I haven't tried it in this specific situation, but I think you could enclose the path in double quotes. Or use a ProcessStartInfo object as the parameter to Process.Start.
Mark Wilkins
+1  A: 

Try doing this:

        string cmdexePath = @"C:\Windows\System32\cmd.exe";
        //notice the quotes around the below string...
        string myApplication = "\"C:\\Windows\\System32\\ftp.exe\"";
        //the /K keeps the CMD window open - even if your windows app closes
        string cmdArguments = String.Format("/K {0}", myApplication);
        ProcessStartInfo psi = new ProcessStartInfo(cmdexePath, cmdArguments);
        Process p = new Process();
        p.StartInfo = psi;
        p.Start();

I think this will get you the behavior you are trying for. Assuming you weren't just trying to see the output in the command window. If you just want to see the output, you have several versions of that answer already. This is just how you can run your app and keep the console open.

Hope this helps. Good luck.

Audie
A: 

If you have control over app.exe, you should be aware of how it functions so I will assume that you do not have control over it's inner workings. In that case, you can try passing a help flag which may or may not give you more info on how to call app.exe. Try something like this:

private startApp()
{
    string command = " -h"; //common help flag for console apps
    System.Diagnostics.Process pRun;
    pRun = new System.Diagnostics.Process();
    pRun.EnableRaisingEvents = true;
    pRun.Exited += new EventHandler(pRun_Exited);
    pRun.StartInfo.FileName = "app.exe";
    pRun.StartInfo.Arguments = command;
    pRun.StartInfo.WindowStyle =  System.Diagnostics.ProcessWindowStyle.Normal

    pRun.Start();
    pRun.WaitForExit();
}
private void  pRun_Exited(object sender, EventArgs e)
{
    //Do Something Here
}
J.Hendrix
A: 

Create a new text file, name it app.bat and put this in there:

app.exe
pause

Now have your form point to that bat file.

SethCoder