Hi, I am trying to send raw xml to a service in Python. I have a the address of the service and my question is how would I wrap XML in python and send it to the service. The address is in the format below.
192.1100.2.2:54239
And say the XML is:
<xml version="1.0" encoding="UTF-8"><header/><body><code><body/>
Anyone know what to do?
This should do the trick.
import socket
import time
command = '<xml version="1.0" encoding="UTF-8"><header/><body><code><body/>'
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect(("192.1100.2.2", 54239))
s.send(command)
time.sleep(2)
resp = s.recv(3000)
print resp
pydoc socket
... should get you started.
PS. Your example IP address looks a bit strange (1100 is greater than 255), but maybe that's just so nobody tries to use it ...