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views:

149

answers:

2

I am trying to use \ifthenelse to do a floating point comparison. This is the pgf/tikz code, which works if \y is integer only, but not otherwise:

\foreach \y in {3,3.5,...,6} {
    ifthenelse{\y<3}{
        ...
    }{
        ...
    }
}
+3  A: 

You can not use floating variables. Use dimens instead of. For example

\newdimen \y 
\y = 3.2pt
\ifdim \y < 3.45pt ... \else ... \fi
Alexey Malistov
+1  A: 

To expand on Alexey's suggestion of using dimensions, here is some working TikZ code that I think will solve your problem:

\documentclass{article}
\usepackage{tikz}
\usepackage{ifthen}
\begin{document}
  \begin{tikzpicture}
    \foreach \y in {3,3.5,...,6} {
      \ifthenelse{\lengthtest{\y pt > 4.5pt}}{
        \node at (0,\y) {\y\ is greater than 4.5!};
      }{
        \node at (0,\y) {\y\ is less than 4.5};
      }
    }
  \end{tikzpicture}
\end{document}
ESultanik