More efficient way to write this Jquery code

Question

Is there a better, more efficient way to write this code? It's a make shift drop down menu that allows user to RSVP for multiple people. Sorry, it's kind of a mess, but I think what I'm doing is clear. If not, I'm at my computer and will respond quickly with more info need be.

 //There's got to be a better way to do this
 $('#guest_num_1').click( function() {
 $('#num_guests a#quant_guests').html("1")
 $('.guest_name_2, .guest_name_3, .guest_name_4, .guest_name_5, .guest_name_6 ').hide()
 });

 $('#guest_num_2').click( function() {
 $('#num_guests a#quant_guests').html("2")
 $('.guest_name_2').fadeIn()
 $('.guest_name_3, .guest_name_4, .guest_name_5, .guest_name_6').hide()
 });

 $('#guest_num_3').click( function() {
 $('#num_guests a#quant_guests').html("3")
 $('.guest_name_2, .guest_name_3').fadeIn()
 $('.guest_name_4, .guest_name_5, .guest_name_6').hide()
 });

 $('#guest_num_4').click( function() {
 $('#num_guests a#quant_guests').html("4")
 $('.guest_name_2, .guest_name_3, .guest_name_4').fadeIn()
 $('.guest_name_5, .guest_name_6').hide()
 });

 $('#guest_num_5').click( function() {
 $('#num_guests a#quant_guests').html("5")
 $('.guest_name_2, .guest_name_3, .guest_name_4, .guest_name_5').fadeIn()
 $('.guest_name_6').hide()
 });

 $('#guest_num_6').click( function() {
 $('#num_guests a#quant_guests').html("6")
 $('.guest_name_2, .guest_name_3, .guest_name_4, .guest_name_5, .guest_name_6').fadeIn()
 });

Answer 1

$('.guest_num').click(function() {
  var n = $(this).attr('href').split('#')[1];
  $('#num_guests a#quant_guests').html(n);
  var curr = $('.guest_name_' + n);
  curr.prevAll().fadeIn();
  curr.fadeIn();
  curr.nextAll().hide();
  return false;
});

On the HTML side:

<a class="guest_num" href="#1">...</a>

Answer 2

use a loop and store this "guest_num_1" and for every eteration change the '1' with the loop index