views:

194

answers:

2

I don't understand why 'x' below converts, but 'y' and 'z' do not.

var list = new List<List<int>>();

IEnumerable<List<int>> x = list;
List<IEnumerable<int>> y = list;
IEnumerable<IEnumerable<int>> z = list;

Does the new covariance feature simply not work on generics of generics or am I doing something wrong? (I'd like to avoid using .Cast<> to make y and z work.)

+5  A: 

"z" is fine in C# 4.0, IEnumerable<T> is covariant. List<T> is however not, you cannot make "y" work.

Intuitively, if it were then this would be valid:

List<IEnumerable<int>> y = list
y.Add(new Stack<int>());

Which breaks the promise that "list" can only contain List<int> elements.

Hans Passant
Ok part of the problem was that 'z' was not working for me because I was still targetting 3.5. Oops. Thanks for the explanation on 'y' not working, that makes sense.
Scott Bilas
+1  A: 

You are making several mistakes here. First, covariance and contravariance are not supported for value types, so whatever you try to do with "int" wouldn't work.

Second, the valid example checking for variance in nested generic types looks more like this:

var list = new List<List<String>>();
IEnumerable<IEnumerable<object>> z = list; 

I can assign List of List of strings to IEnumerable of IEnumerables of objects, which is covariance. For more info, check out Covariance and Contravariance FAQ.

Alexandra Rusina