SQL select statement with increment

Question

Currently I'm using a for statement in PHP to get all the months for this SQL statement, but would like to know if I can do it all with SQL.

Basically I have to get the average listing price, and the average selling price for each month going back 1 year where the sellingdate = the month.

simple with PHP, but that creates 12 database hits.

I'm trying the sql statment below, but it returns listings totally out of order

SELECT 
avg(ListingPrice), 
avg(SellingPrice),
count(ListingDate),
DATE(SellingDate) as date,
MONTH(SellingDate) as month,
YEAR(SellingDate) as year
FROM `rets_property_resi` 
WHERE Area = '5030'
AND Status = 'S'
AND SellingDate "less then" = 'NOW()'
GROUP BY month
ORDER BY month desc
LIMIT 0,12

the "less then" is getting stripped from the statment, so please replace "less then" with the proper code

Output:

867507.142857   877632.492063   63  1996-12-24  12  1996
971355.833333   981533.333333   60  1997-11-18  11  1997
949334.328358   985453.731343   67  1997-10-23  10  1997
794150.000000   806642.857143   70  1996-09-20  9   1996
968371.621622   988074.702703   74  1997-08-21  8   1997
1033413.366337  1053018.534653  101 1997-07-30  7   1997
936115.054795   962787.671233   73  1996-06-07  6   1996
875378.735632   906921.839080   87  1996-05-16  5   1996
926635.616438   958561.643836   73  2010-04-13  4   2010
1030224.472222  1046332.291667  72  2010-03-31  3   2010
921711.458333   924177.083333   48  1997-02-28  2   1997
799484.615385   791551.282051   39  1997-01-15  1   1997

As you can see, it pulls from random dates, I need to to pull from 2010-03, 2010-02, 2010-01, etc...

any help is appreciated!

Answer 1

Try this:

SELECT 
    avg(ListingPrice), 
    avg(SellingPrice),
    count(ListingDate),
    MONTH(SellingDate) as month,
    YEAR(SellingDate) as year
FROM `rets_property_resi` 
WHERE Area = '5030'
    AND Status = 'S'
    AND SellingDate <= NOW()
GROUP BY year, month
ORDER BY year desc, month desc
LIMIT 0,12