Count numbers in words.

Question

I need an assembler 8080 software which counts words (delimited by space) which have more than two number in it.

Example : this sh0uld b3 l1ke th1s would print : 0 words

but Example : this sh0uld b3 l1k3 th1s f000k would print : 2 words <- word l1k3 contain number 1,3 and f000k number 0,0,0

the output should be displayer in hexadecimal format (optional)

Answer 1

My suggestion: if you want to practice this, spend some time at "The Art of Assembly Language" website at http://homepage.mac.com/randyhyde/webster.cs.ucr.edu/www.artofasm.com/DOS/index.html. There you will learn everything you ever wanted to know about 8086 assembly language.

It is not 8080 is a simpler form of the language, but the concepts and principles are the same.