I am using an XSL transformation on an xml file to create an xml document. The problem i am running into is that when i go to view the generated source (the transformed source) i can't see the DOCTYPE attribute of the html so i don't know if its being emitted properly.
Is there any way to view the doctype in this way?
I haven't tried it recently but I believe xsl:output can be used for this, see this tutorial and the options under the various attributes there.
Read about the doctype-system and doctype-public attributes of <xsl:output>.
This often happens when you serialize the result of the transformation (document tree) yourself. How do you run the transformation and obtain its result?
If you have transitional xhtml, you should include the following xsl:output tag:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html"
doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"
doctype-public="-//W3C//DTD XHTML 1.0 Transitional//EN" />
<xsl:template match="/">
<html>
<head><title>Test</title></head>
<body></body>
</html>
</xsl:template>
</xsl:stylesheet>
This example produces the following output (with an arbitrary input XML):
<!DOCTYPE html
PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Test</title>
</head>
<body></body>
</html>
I must have a weird system, in my case i actually had to just use the doctype as an include file. I tried the suggestions but for some reason it wasnt rendering the html properly. Its kind of a weird system they have here at work and im not sure how it works.