Matlab: How to create a 3D matrix?

Question

Hi,

Does anyone know how to define a 3D matrix in matlab, for example a matrix of size (8 x 4 x 20) or add a 3rd dimension to an existing 2D matrix?

Thank you.

Answer 1

If you want to define a 3D matrix containing all zeros, you write

A = zeros(8,4,20);

All ones uses ones, all NaN's uses NaN, all false uses false instead of zeros.

If you have an existing 2D matrix, you can assign an element in the "3rd dimension" and the matrix is augmented to contain the new element. All other new matrix elements that have to be added to do that are set to zero.

For example

B = magic(3); %# creates a 3x3 magic square
B(2,1,2) = 1; %# and you have a 3x3x2 array

Answer 2

I use Octave, but Matlab has the same syntax.

Create 3d matrix:

octave:3> m = ones(2,3,2)
m =

ans(:,:,1) =

   1   1   1
   1   1   1

ans(:,:,2) =

   1   1   1
   1   1   1

Now, say I have a 2D matrix that I want to expand in a new dimension:

octave:4> Two_D = ones(2,3)
Two_D =
   1   1   1
   1   1   1

I can expand it by creating a 3D matrix, setting the first 2D in it to my old (here I have size two of the third dimension):

octave:11> Three_D = zeros(2,3,2)
Three_D =

ans(:,:,1) =

   0   0   0
   0   0   0

ans(:,:,2) =

   0   0   0
   0   0   0



octave:12> Three_D(:,:,1) = Two_D
Three_D =

ans(:,:,1) =

   1   1   1
   1   1   1

ans(:,:,2) =

   0   0   0
   0   0   0

Answer 3

Create a 3D matrix

A = zeros(20, 10, 3);   %# Creates a 20x10x3 matrix

Add a 3rd dimension to a matrix

B = zeros(4,4);  
C = zeros(size(B,1), size(B,2), 4);  %# New matrix with B's size, and 3rd dimension of size 4
C(:,:,1) = B;                        %# Copy the content of B into C's first set of values

zeros is just one way of making a new matrix. Another could be A(1:20,1:10,1:3) = 0 for a 3D matrix. To confirm the size of your matrices you can run: size(A) which gives 20 10 3.

There is no explicit bound on the number of dimensions a matrix may have.