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147

answers:

2

Another XSD question - how can I achieve that the following XML elements are both valid:

<some-element>
  <type>1</type>
  <a>...</a>
</some-element>

<some-element>
  <type>2</type>
  <b>...</b>
</some-element>

The sub-elements (either <a> or <b>) should depend on the content of <type> (could also be an attribute). It would be so simple in RelaxNG - but RelaxNG doesn't support key integrity :(

Is there a way to implement this in XSD?

Note: XML schema version 1.1 supports <xs:alternative>, which might be a solution, but afaik no reference implementation (e.g. libxml2) supports this yet. So I'm searching for workarounds. The only way I've come up with is:

<type>1</type>
<some-element type="1">
    <!-- simple <xs:choice> between <a> and <b> goes here -->
    <a>...</a>
</some-element>
<!-- and now create a keyref between <type> and @type -->
+1  A: 

No, XML Schema 1.0 cannot do this.

John Saunders
A: 

The best solution is to remove the <type/> element and only have a xs:choice for <a/> and <b/> and let the application consuming the xml sort out the type.

Another solution might be to have a xs:choice for <a/> and <b/> use an xslt script to do a validation of the <type/> element in relation to <a/> and <b/>.

First validate the xml against the xmlschema then use the xslt to do a transformation on it, if the result of the transform is empty string it is valid otherwise show the resulting string as an error message.

Something like this...

XmlSchema:

  <xs:element name="some-element">
    <xs:complexType>
      <xs:sequence>
        <xs:element name="type" type="xs:integer" />
        <xs:choice>
          <xs:element name="a" type="xs:string" />
          <xs:element name="b" type="xs:string" />
        </xs:choice>
      </xs:sequence>
    </xs:complexType>
  </xs:element>
</xs:schema>

Xslt:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:demo="uri:demo:namespace">
  <xsl:output method="text" />
  <xsl:template match="/demo:some-element">
    <xsl:if test="type = 1 and not(demo:a)">
      When type equals 1 element a is requred.
    </xsl:if>
    <xsl:if test="type = 2 and not(demo:b)">
      When type equals 2 element b is requred.
    </xsl:if>
  </xsl:template>
</xsl:stylesheet>
Jens Granlund