C#: Finding Out Which Monday Is The 3rd Monday Of The Month?

Question

If I'm writing some C# code that runs through a year of dates (iterating by day) and want something special to happen every 3rd Monday of the month, how can I accomplish this?

In other words, what is the best way to find which Monday of the month a current Monday is?

Answer 1

Find the Monday that is between the 15th and the 21st, inclusive.

Answer 2

public bool IsThirdMondayOfMonth(DateTime dt)
{
  if(dt.DayOfWeek == DayOfWeek.Monday && dt.Day > 14 && dt.Day <= 21)
  {
    return true;
  }
  return false;
}

Answer 3

I don't know if there is a date manipulation library to do what you want, but you can write your own functions pretty easily:

using System;

class Program {
    static void Main(string[] args) {
        int year = 2010;
        int month = 05;
        DateTime thirdMonday = ThirdMonday(year, month);
    }

    private static DateTime ThirdMonday(int year, int month) {
        for (int day = 1; day <= DateTime.DaysInMonth(year, month); ++day) {
            DateTime dt = new DateTime(year, month, day);
            if (dt.DayOfWeek == DayOfWeek.Monday) {
                return dt.AddDays(14);
            }
        }
        // this should never happen
        throw new Exception();
    }
}

Answer 4

I don't think your "in other words" really restates the problem that you describe first, so I'll answer both.

Here's a fairly simple method that will determine the nth occurrence of a particular day of the week in a given month in a given year.

public static DateTime DayOccurrence(int year, int month, DayOfWeek day, 
    int occurrenceNumber)
{
    DateTime start = new DateTime(year, month, 1);
    DateTime first = start.AddDays((7 - ((int)start.DayOfWeek - (int)day)) % 7);

    return first.AddDays(7 * (occurrenceNumber - 1));
}

Determining which Monday (or any other day) of the month a date is is much easier; just take the ceiling of the day of the month / 7:

public static int DayOccurrence(DateTime date)
{
    return (int)Math.Ceiling(date.Day / 7.0);
}