I am trying to use Pythons LXML library to great a GPX file that can be read by Garmin's Mapsource Product. The header on their GPX files looks like this
<?xml version="1.0" encoding="UTF-8" standalone="no" ?>
<gpx xmlns="http://www.topografix.com/GPX/1/1"
creator="MapSource 6.15.5" version="1.1"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.topografix.com/GPX/1/1 http://www.topografix.com/GPX/1/1/gpx.xsd">
When I use the following code:
xmlns="http://www.topografix.com/GPX/1/1"
xsi="http://www.w3.org/2001/XMLSchema-instance"
schemaLocation="http://www.topografix.com/GPX/1/1 http://www.topografix.com/GPX/1/1/gpx.xsd"
version="1.1"
ns = "{xsi}"
getXML = etree.Element("{"+xmlns+"}gpx",version=version, attrib={"{xsi}schemaLocation" : schemaLocation}, creator='My Product', nsmap={'xsi':xsi, None:xmlns})
print(etree.tostring(getXML, xml_declaration=True, standalone='Yes', encoding="UTF-8", pretty_print=True))
I get:
<?xml version=\'1.0\' encoding=\'UTF-8\' standalone=\'yes\'?>
<gpx xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://www.topografix.com/GPX/1/1" xmlns:ns0="xsi"
ns0:schemaLocation="http://www.topografix.com/GPX/1/1 http://www.topografix.com/GPX/1/1/gpx.xsd"
version="1.1" creator="My Product"/>
Which has the annoying 'ns0' tag. This might be perfectly valid XML but Mapsource does not appreciate it.
Any idea how to get this to not have the ns0 tag?