How do I subtract two dates in Django/Python?

Question

Hi!

I'm working on a little fitness tracker in order to teach myself Django. I want to graph my weight over time, so I've decided to use the Python Google Charts Wrapper. Google charts require that you convert your date into a x coordinate. To do this I want to take the number of days in my dataset by subtracting the first weigh-in from the last weigh-in and then using that to figure out the x coords (for example, I could 100 by the result and increment the x coord by the resulting number for each y coord.)

Anyway, I need to figure out how to subtract Django datetime objects from one another and so far, I am striking out on both google and here at the stack. I know PHP, but have never gotten a handle on OO programming, so please excuse my ignorance. Here is what my models look like:

class Goal(models.Model):
  goal_weight = models.DecimalField("Goal Weight",max_digits=4, decimal_places=1)
  target_date = models.DateTimeField("Target Date to Reach Goal")
  set_date = models.DateTimeField("When did you set your goal?")
  comments = models.TextField(blank=True)
  def __unicode__(self):
  return unicode(self.goal_weight)

class Weight(models.Model):
 """Weight at a given date and time
 """
 goal = models.ForeignKey(Goal)
 weight = models.DecimalField("Current Weight",max_digits=4, decimal_places=1)
 weigh_date = models.DateTimeField("Date of Weigh-In")
 comments = models.TextField(blank=True)
 def __unicode__(self):
  return unicode(self.weight)
 def recorded_today(self):
  return self.date.date() == datetime.date.today()

Any ideas on how to proceed in the view? Thanks so much!

Answer 1

Django datetime objects are just regular Python datetime objects. When you subtract one datetime from another you get a timedelta object.

If you are looking to subtract a length of time from a datetime you need to subtract a timedelta object from it. For example:

>>> from datetime import datetime, timedelta
>>> now = datetime.now()
>>> print now
2010-05-18 23:16:24.770533
>>> this_time_yesterday = now - timedelta(hours=24)
>>> print this_time_yesterday
2010-05-17 23:16:24.770533
>>> (now - this_time_yesterday).days
1

Answer 2

You can just subtract the dates directly, which will yield a datetime.timedelta object:

dt = weight_now.weight_date - weight_then.weight_date

A timedelta object has fields for days, seconds, and microseconds. From there, you can just do the appropriate math. For example:

hours = dt.seconds / 60 / 60    # Returns number of hours between dates
weeks = dt.days / 7             # number of weeks between dates