I've seen this format function referenced on several sites, but none of them have an explicit example of how to pass in a number into the function.
I've tried '12345'.format('0.00') which I believe is how it should be written, but it gives me the error that the object doesn't support the property or method. I've also tried Number('12345').format('0.00'); var num = '12345' // num.format('0.00'); format('0.00','12345') and have even tried using numbers instead of strings 12345.format(0.00). Am I missing something really obvious here?
Included copy of function for reference so you don't have to go to the site (with all missing pieces filled in).
/**
* I ♥ Google
*/
String.prototype.stripNonNumeric = function() {
var str = this + '';
var rgx = /^\d|\.|-$/;
var out = '';
for( var i = 0; i < str.length; i++ ) {
if( rgx.test( str.charAt(i) ) ) {
if( !( ( str.charAt(i) == '.' && out.indexOf( '.' ) != -1 ) ||
( str.charAt(i) == '-' && out.length != 0 ) ) ) {
out += str.charAt(i);
}
}
}
return out;
};
/**
* Formats the number according to the 'format' string; adherses to the american number standard where a comma is inserted after every 3 digits.
* note: there should be only 1 contiguous number in the format, where a number consists of digits, period, and commas
* any other characters can be wrapped around this number, including '$', '%', or text
* examples (123456.789):
* '0' - (123456) show only digits, no precision
* '0.00' - (123456.78) show only digits, 2 precision
* '0.0000' - (123456.7890) show only digits, 4 precision
* '0,000' - (123,456) show comma and digits, no precision
* '0,000.00' - (123,456.78) show comma and digits, 2 precision
* '0,0.00' - (123,456.78) shortcut method, show comma and digits, 2 precision
*
* @method format
* @param format {string} the way you would like to format this text
* @return {string} the formatted number
* @public
*/
Number.prototype.format = function(format) {
if (!(typeof format == "string")) {return '';} // sanity check
var hasComma = -1 < format.indexOf(','),
psplit = format.stripNonNumeric().split('.'),
that = this;
// compute precision
if (1 < psplit.length) {
// fix number precision
that = that.toFixed(psplit[1].length);
}
// error: too many periods
else if (2 < psplit.length) {
throw('NumberFormatException: invalid format, formats should have no more than 1 period: ' + format);
}
// remove precision
else {
that = that.toFixed(0);
}
// get the string now that precision is correct
var fnum = that.toString();
// format has comma, then compute commas
if (hasComma) {
// remove precision for computation
psplit = fnum.split('.');
var cnum = psplit[0],
parr = [],
j = cnum.length,
m = Math.floor(j / 3),
n = cnum.length % 3 || 3; // n cannot be ZERO or causes infinite loop
// break the number into chunks of 3 digits; first chunk may be less than 3
for (var i = 0; i < j; i += n) {
if (i != 0) {n = 3;}
parr[parr.length] = cnum.substr(i, n);
m -= 1;
}
// put chunks back together, separated by comma
fnum = parr.join(',');
// add the precision back in
if (psplit[1]) {fnum += '.' + psplit[1];}
}
// replace the number portion of the format with fnum
return format.replace(/[\d,?\.?]+/, fnum);
};