How to print arguments passed to configure script?

Question

Hi,

I'm trying to print arguments passed to a ./configure script. Calling 'echo' on $BASH_ARGV will just print the last set of arguments. For example if I run:

./configure --enable-foo --enable-bar

echo $BASH_ARGV will print only "--enable-bar"

How do I print all the arguments? Thanks!

Answer 1

You can use $@ and $* to refer to parameters.

echo "$@"; should do it. A little more information here

Answer 2

Since it's an array, you need to do this to get all the elements:

echo ${BASH_ARGV[@]}

or use a loop to iterate over them.

Note: they'll be output in reverse order.

Answer 3

There is a variable called ac_configure_args that contains what I need. Thanks for the help everyone.