what's wrong with this code?

Question

$child= array();
$i = 0;

while($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
    $child[i] = $row['userId'];
    $i++;
} 

$i = 0;
while($i<=5)
{
    echo $child[i];
    $i++;
}

It is printing same value.

Answer 1

You are using i for the array index instead of $i:

$child[i]

This should be $child[$i]. Because the i in $child[i] is interpreted as a constant (value of constant i is used as index) or if there is no such constant as string. You can get a variable/value dump with var_dump.

Answer 2

you forgot an $i in $child[i].. should be $child[$i] ;)

Answer 3

$child= array();
$i = 0;

while($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
    $child[$i] = $row['userId'];
    $i++;
} 

 $i = 0;
while($i<=5)
{
    echo $child[$i];
    $i++;
}

You weren't calling $i, but "i"

Answer 4

If you want numeric indexes you can do without $i .. try ..

while($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
    $child[] = $row['userId'];
} 

for($i=0;$i<5;$i++)
{    
echo $child[$i].' <br />;
}

Hope it helps.