Can i use a generic implicit or explicit operator? C#

Question

How do i change the following statement so it accepts any type instead of long? Now here is the catch, if there is no constructor i dont want it compiling. So if theres a constructor for string, long and double but no bool how do i have this one line work for all of these support types?

ATM i just copied pasted it but i wouldnt like doing that if i had 20types (as trivial as the task may be)

public static explicit operator MyClass(long v) { return new MyClass(v); }

Answer 1

Use Object type, if I'm not mistaken.

public static explicit operator MyClass(object v) { return new MyClass(v); }

Answer 2

Maybe it works:

public static explicit operator MyClass<T>(T t) where T:new()
{ 
  return new MyClass(t);
}

EDIT

I checked your request just now and found sth weird. "So if theres a constructor for string, long and double but no bool" Can you tell me why you want to do this.

EDIT

I tried on my machine, it seems that generic types can't be used in explicit methods. Maybe we can only go back to an object parameter?

Answer 3

Now I can tell you that the answer to you question is "No, we can't" because:

User-defined conversion must convert to or from the enclosing type.

That's why we can't use generic types here.

public class Order
{
    public string Vender { get; set; }
    public decimal Amount { get; set; }
}

public class AnotherOrder
{
    public string Vender { get; set; }
    public decimal Amount { get; set; }
    public static explicit operator AnotherOrder(Order o)
    {
        //this method can be put in Order or AnotherOrder only
    }
}