How to use regex to strip [a-z]/[a-z]/ from a string?

Question

Say a string is abc/xyz/IMPORTANT/DATA/@#!%@!%, and I just want IMPORTANT/DATA/!%#@%!#%

I am terrible at regex, and really haven't learned JavaScript API yet

Answer 1

If the text is always like your current example you might be able to simply use substring and indexOf to cut it starting from the second occurence of the "/".

Otherwise /([^\/]+\/[^\/]+\/)/, or Blair's answer might be a good regexp to use. Or /^([^\/]+\/[^\/]+\/)/ if it has to start at the beginning of the string.

Answer 2

I think

yourstring.replace(/[a-z]+\/[a-z]+\/(.+)/g, "$1");

Answer 3

Use indexOf and substring. You don't need regex for this.

You can use the start parameter to indexOf to search from a given position. If you search after the first /, you can find the index of the second /.

s = "abc/def/ghi/jkl";
s = s.substring(s.indexOf('/', s.indexOf('/') + 1) + 1);
document.writeln(s); // "ghi/jkl"

Note that this assumes that there will always be at least two /. If there isn't, this will keep s as it is.

s = "abc/xyz";
s = s.substring(s.indexOf('/', s.indexOf('/') + 1) + 1);
document.writeln(s); // "abc/xyz"

If you want to use regex anyway, it's something like this:

s = "abc/def/ghi/jkl";
s = s.replace(/[a-z]+\/[a-z]+\//, '');
document.writeln(s); // "ghi/jkl"

Again, this assumes that there will always be at least two /.