views:

114

answers:

4

Hi Guys,

A colleague asked me about a Regular expression problem, and I can't seem to find and answer for him.

We're using boundaries to highlight certain lengths of text in a text editor, but here's some sample code that shows the problem:

<script type="text/javascript">
var str = "Alpha , Beta, Gamma Delta Epsilon, AAlphaa, Beta Alpha<br/>";
var rx = new RegExp('\bAlpha\b','gim');

document.write(str.replace(/\b(Alpha)\b/gim, '-- $1 --'));
document.write(str.replace(rx, '== $1 =='));
</script>

The issue is, the first literal str.replace works, but the RegExp option doesn't.

I've got the same behaviour in IE and FF, anyone know why ?

+2  A: 

I'm guessing it doesn't work because you need to escape the backslashes in your string that you pass to RegExp. You have this:

var rx = new RegExp('\bAlpha\b','gim');

You need this:

var rx = new RegExp('\\bAlpha\\b','gim');

The string you passed to RegExp has 2 backspace characters in it, since \b is the escape sequence for inserting a backspace into a string. You need to escape each backslash with another backslash.

A. Levy
Doh, of course; Thanks!
Russ C
Also missing the capture parens: \\b(Alpha)\\b
Alex K.
+1  A: 

RegExp needs to have the escape character escaped:

new RegExp('\\bAlpha\\b')
Andy E
+1  A: 

This is a string issue. \b in a string literal is a backspace!

RegExp('\\bAlpha\\b','gim'); would be the correct form

Matt
+1  A: 

There are 2 ways to write your regular expressions in Javascript

  1. literal
  2. RegExp object

In literal way, you use as you learned in your textbook, e.g. /balabala/ But in RegExp object, regular expression is written as a string.

Try the following codes, you know what string behaves in javascript.

alert("O\K");
alert("O\\K");

There's another occasion when Regexp written in a textarea or input box. For example,

http://www.pagecolumn.com/tool/regtest.htm

In this case, \ in Regexp need not be escaped.

unigg