tags:

views:

43

answers:

3

Here is a simplified table structure:

TABLE products (
 product_id INT (primary key, auto_increment),
 category_id INT,
 product_title VARCHAR,
 etc
);

TABLE product_photos (
 product_photo_id (primary key, auto_increment),
 product_id INT,
 photo_href VARCHAR,
 photo_order INT
);

A product can have multiple photos, the first product photo for each product (based on the photo_order) is the default photo.

Now, I only need all of the photos on the product details page, but on pages where I am listing multiple products, for example a product directory page, I only want to display the default photo.

So what I am trying to do, is query a list of products including the default photo for each product.

This obviously doesn't work, it will return all photos with the product info duplicated for each photo:

SELECT p.*, ph.*
FROM products AS p
LEFT JOIN product_photos AS ph
ON p.product_id=ph.product_id
ORDER BY p.product_title ASC

I need to figure out how to do something like this, but I don't know the syntax (or if it is possible)

SELECT p.*, ph.*
FROM products AS p
LEFT JOIN product_photos AS ph
    ON p.product_id=ph.product_id  **ORDER BY ph.photo_order ASC LIMIT 1**
ORDER BY p.product_title ASC

Edit: I figured out a solution with help from the answers below, thanks all!

SELECT p.*, ph.*
FROM products AS p
LEFT JOIN product_photos AS ph 
    ON p.product_id=ph.product_id
    AND ph.photo_order =
    (
        SELECT MIN(z.photo_order)
        FROM product_photos AS z
        WHERE z.product_id=p.product_id
    )
GROUP BY p.product_id
ORDER BY p.product_title ASC
+1  A: 

Use:

SELECT p.*,
       pp.*
  FROM PRODUCTS p
  JOIN PRODUCT_PHOTOS pp ON pp.product_id = p.product_id
  JOIN (SELECT x.product_id,
               MIN(x.photo_order) AS default_photo
          FROM PRODUCT_PHOTOS x
      GROUP BY x.product_id) y ON y.product_id = pp.product_id
                              AND y.default_photo  = pp.photo_order
OMG Ponies
i don't know that this does what he's asking. he was specific that the photo_order field be used, not the product_photo_id field.
nathan gonzalez
It does exactly what is needed, I just try to avoid subqueries when I can, hence the other answer.
Wrikken
@Wrikken: A join to a derived table/inline view isn't a subquery. To me, at least...
OMG Ponies
@OMG Ponies agreed on the derived table. did you change your anwser or did i completely misread it? apologies if i was in the wrong.
nathan gonzalez
@OMG Ponies ohoh, not getting into that. Not quite flame-war-bait, but whether a derived table is a subquery is very open for debate, which I will not start now. And it wasn't a criticism, my disuse of subqueries and / or derived tables sometimes borders the illogical.
Wrikken
+2  A: 
SELECT p.*, ph.*
FROM products AS p
JOIN product_photos AS ph
ON p.product_id=ph.product_id
LEFT JOIN product_photos AS ph2
ON p.product_id=ph2.product_id
AND ph2.photo_order < ph.photo_order
WHERE ph2.photo_order IS NULL
ORDER BY p.product_title ASC

It won't protect you against duplicate product_id / photo_orders combo though, you could add a GROUP BY on p.id if that's the case.

Wrikken
Thanks for the reply!
Rob
Nice job. No sub query/derived table. Just need indexes on product_id and photo_order.
Marcus Adams
A: 
SELECT ...
  ....
GROUP BY p.product_id
Ignacio Vazquez-Abrams
Thanks for the reply, although this solution won't honor the photo_order column.
Rob
Try reversing the sort order.
Ignacio Vazquez-Abrams