If a string in Perl 5 passes looks_like_number
, it might as well be a number. For instance,
my $s = "10" + 5;
results in $s
being assigned 15
.
Are there any cases where a string does not behave like it's numeric equivalent would have?
If a string in Perl 5 passes looks_like_number
, it might as well be a number. For instance,
my $s = "10" + 5;
results in $s
being assigned 15
.
Are there any cases where a string does not behave like it's numeric equivalent would have?
I can only think of one: when checking for truth. Strings that are equivalent to 0
, but that are not "0"
, such as "0.0"
, "0 but true"
, "0e0"
, etc. all pass looks_like_number
and evaluate to 0
in numeric context, but are still considered true values.
An equivalent number and string behave differently in hash keys -- or, more generally, any time we stringify a largish number:
my (%g, %h);
$g{ 1234000000000000 } = undef; # '1.234e+015' => undef
$h{'1234000000000000'} = undef; # '1234000000000000' => undef
Note that we are still within the range where Perl can store the number precisely:
> perl -e 'printf qq{%.f\n}, 1234000000000000 + $_ for +1, 0, -1'
1234000000000001
1234000000000000
1233999999999999
When dealing with bitwise operators. 123 ^ 456
is 435, but "123" ^ "456"
is "\x05\x07\x05"
. The bitwise operators work numerically if either operand is a number.