I have a line like this:
pad (2) = 0x0041
I wanna change the hex into decimal and the expected result is
pad (2) = 65
I just tried :%s/\(.*\) = \(.*\)/\1 = \=printf("%d", submatch(2)), but it failed.
Would you help to solve this?
views:
39answers:
2
+2
A:
Vim has a str2nr() function to convert different number representations to their decimal values. To convert hex values you could use it like this:
s/0x[0-9a-fA-F]\+/\=str2nr(submatch(0), 16)
sth
2010-06-07 10:31:19
oh. Thank you very much and your method is quite useful.but if there are [a-f] in the statement the method fails.
stefanzweig
2010-06-07 10:51:17
@stefan: Oops, yes of course :), I should extend the match to also include those characters...
sth
2010-06-07 11:07:59
Thank you very much. It works definitely.
stefanzweig
2010-06-08 12:46:52
+1
A:
Your code is almost ok, but, according to the documentation:
When the substitute string starts with "\=" the remainder is interpreted as an expression. This does not work recursively: a substitute() function inside the expression cannot use "\=" for the substitute string.
So, you may change your code to
%s/\(.*\) = \(.*\)/\=submatch(1)." = ".printf("%d", submatch(2))
ZyX
2010-06-07 13:11:09
Hi ZyX, Thank you very much. I will try your method. Now I have a good way to convert my logs. :-)
stefanzweig
2010-06-08 12:48:16
if you're not changing anything in the first half (just matching), you might want to consider using `\zs` to change where the start of the replaced string is:
rampion
2010-06-08 13:28:52