why aren't strongly typed C++0x enumerations comparable to each other?

Question

why aren't strongly typed C++0x enumerations comparable to each other?

Answer 1

If you use strongly typed enumerations, it's like making your enum a realy type, a class. Then it follows the same rules as for classes.

Classes instances can't be compared to each other. You have to define a comparison function (or member function) to make them comparable.

Then making an enumeration strongly typed makes it follows this very rule.