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74

answers:

1

I'm looking for a way to modify properties on a dynamic C# 4.0 object with the name of the property known only at runtime.

Is there a way to do something like (ExpandoObject is just used as an example, this could be any class that implements IDynamicMetaObjectProvider):

string key = "TestKey";
dynamic e = new ExpandoObject();
e[key] = "value";

Which would be equivalent to:

dynamic e = new ExpandoObject();
e.TestKey = "value";

Or is the only way forward reflection?

+1  A: 

Not very easily, no. Reflection doesn't work, since it assumes a regular type model, which is not the full range of dynamic. If you are actually just talking to regular objects, then just use reflection here. Otherwise, I expect you may want to reverse-engineer the code that the compiler emits for a basic assignment, and tweak it to have a flexibly member-name. I'll be honest, though: this isn't an attractive option; a simple:

dynamic foo = ...
foo.Bar = "abc";

translates to:

if (<Main>o__SiteContainer0.<>p__Site1 == null)
{
    <Main>o__SiteContainer0.<>p__Site1 = CallSite<Func<CallSite, object, string, object>>.Create(Binder.SetMember(CSharpBinderFlags.None, "Bar", typeof(Program), new CSharpArgumentInfo[] { CSharpArgumentInfo.Create(CSharpArgumentInfoFlags.None, null), CSharpArgumentInfo.Create(CSharpArgumentInfoFlags.Constant | CSharpArgumentInfoFlags.UseCompileTimeType, null) }));
}
<Main>o__SiteContainer0.<>p__Site1.Target(<Main>o__SiteContainer0.<>p__Site1, foo, "abc");
Marc Gravell
Thanks Marc - I thought I'd been missing something obvious but obviously not! :) Have you got any links to a good example of how to do code emission so I can give this a go? If I can get it going this looks like something work sharing!
Kieran Benton
@Kieran - it depends what you need. It didn't *sound* like you needed emission (the code I posted was just a sample of how ugly it is).
Marc Gravell