Hello,
I'm having this problem that's driving me nuts.
I've got a MySQL database in which there is a table that contains a text field. I am querying the table in PHP and trying to put the content of the text field for each row into a var.
I am doing something like this:
for ($i=0;$i<$nbrows;$i++){
$id = $data[$i]['ID'];
$description = $data[$i]['DESCRIPTION'];
$mystring .= '<div>'.$id.': '.$description.'</div>';
}
DESCRIPTION is my text field.
I'll pass on the details. The $data array is built from mysql_fetch_array($result). I also tried using objects instead, as I use mysql_fetch_object for all my other routines, but there is no change.
Anyway, the problem is this: if I do "echo $description;" then it works. I am getting my text field data as expected. The problem is that I don't want to output it directly, but add it to a concatenated string, and that is not working. What happens in that case is it seems to be taking $description for some kind of array or object. To make the above example work, I have the replace the string with:
$mystring .= '<div>'.$id.': '.$description[0].'</div>';
So in the concatenated string code, if I treat $description as an array, it works, but obviously I am getting only one letter. (it doesn't actually seem to be an array because I can't implode it).
I tried a million things but I just can't make this work unless I use echo, but that is not what I am trying to do.
There is no issue with fields that aren't text.
Thanks for any ideas!