How to access model in jquery

Question

Hi,

The question here is very simple

This is my view

<%@ Control Language="C#" 
    Inherits="System.Web.Mvc.ViewUserControl<GetmoreRevamp.BAL.Product>" %>
<link href="<%=Url.Content("~/Content/AddToCart.css")%>" rel="stylesheet"
      type="text/css" />
<link href="<%=Url.Content("~/Scripts/jquery-1.4.1.js")%>" type="text/javascript" />

<script type="text/javascript">
    function submitForm(formData) {
        var tdata = $(formData).serialize();
        $.ajax({
            type: "POST",
            url: '<%= Url.Action("AddToCart","Cart")%>',
            data: tdata,
            contentType: 'application/json; charset=utf-8',
            datatype: "json",
            success: function(result) { success(result); }
        });
        return false;
    }
    function success(result) {
        alert("success:" + result.success);
    }  
</script>

<% using (Html.BeginForm("AddToCart", "Cart ", Model, FormMethod.Post,
             new { onsubmit = "return submitForm('this');" })) {%>
<div class="prishosbtn">
    <a rel="prettyPhoto" href="" id="buy">
        <%Response.Write("<input type=\"image\" class=\"imgClass\" alt=\"" +
                         (Model != null && Model.ProductName != null ?
                                       Model.ProductName : "KOEB") + "\" src=\"" +
                        Url.Content("~/pics/undersider/listevisning/kob-knap.png") +
                          "\" id=\"ImageButton\" name=\"ImageButton\" />");%>
    </a>
</div>
<%}%>

This is my controller

using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.Mvc;
using GetmoreRevamp.WEB.Models;
using GetmoreRevamp.WEB.Models.BLLModels;
using System.Web.Security;
using System.Security.Principal;
using GetmoreRevamp.WEB.Utilities;
using GetmoreRevamp.BAL;

namespace GetmoreRevamp.WEB.Controllers
{
    public class CartController : Controller
    {
        //
        // GET: /Cart/
        public ActionResult Index()
        {
            return View("Cart");
        }

        [AcceptVerbs(HttpVerbs.Post)]
        public ActionResult AddToCart(Product product)
        {
            JsonResult result = new JsonResult();
            OrderHeader orderHeader = 
                Session[Constants.CurrentlySessionOrderHeader] as OrderHeader;
            if (orderHeader == null)
            {
                orderHeader = new OrderHeader();
            }
            if (product != null && product.ProductGuid != null &&
                string.Equals(product.ProductGuid, string.Empty))
            {
                orderHeader.AddOrderLineItem(1, product);
                orderHeader.Calculate();
                Session[Constants.CurrentlySessionOrderHeader] = orderHeader;
                //Default redirection Must be changed when actual view is created
                result.Data = true;
            }
            else
            {
                //Default redirection Must be changed when actual view is created
                result.Data = false;
            }
            return result;
        }
    }
}

"Product" is defined in bal. Product contains other business entities. What i simply want to do is to access the model with which view is binded in jquery and then post it to my action method in cart controller. i do not want to post the id of product. I want to post the actual model via jquery to my action method. I am a total newbie in this. so any help and most imp simple solution will be preferred

Answer 1

Hey,

MVC matches field names to the business object in the action method, so if Product has a ProductID field, there should be a:

Html.TextBox("ProductID")

declaration, or use the TextBoxFor method in MVC 2. I'm pretty sure that's still how it works even when posting using JQuery. The model binder handles the process of taking the form fields and passing them to the product object. But, all of the fields have to be within the form that you are posting to the server, or you have to explicitly pass the parameters where you pass the tdata variable...

HTH.