Hi to all,
I need to escape the regular expression special characters using java script.How can i achieve this?Any help should be appreciated.
Hi to all,
I need to escape the regular expression special characters using java script.How can i achieve this?Any help should be appreciated.
Use the backslash to escape a character. For example:
/\\d/
This will match \d instead of a numeric character
With \
you escape special characters
Escapes special characters to literal and literal characters to special.
E.g: /(s)/ matches '(s)' while /(\s)/ matches any whitespace and captures the match.
Hi Redi & BEn,
Thanks for your quick reply.But i need to escape all the special characters of regular expression.I have try by this code,But i can't achieve the result.
RegExp.escape=function(str)
{
if (!arguments.callee.sRE) {
var specials = [
'/', '.', '*', '+', '?', '|',
'(', ')', '[', ']', '{', '}', '\\'
];
arguments.callee.sRE = new RegExp(
'(\\' + specials.join('|\\') + ')', 'gim'
);
}
return str.replace(arguments.callee.sRE, '\\$1');
}
function regExpFind() {
<%--var regex = new RegExp("\\[munees\\]","gim");--%>
var regex= new RegExp(RegExp.escape("[Munees]waran"));
<%--var regex=RegExp.escape`enter code here`("[Munees]waran");--%>
alert("Reg : "+regex);
}
What i am wrong with this code?Please guide me.