MySql Row Number?

Question

Is there any way I can get the actual row number from a query?

I want to be able to order a table called league_girl by a field called score; and return the username and the actual row position of that username.

I'm wanting to rank the users so i can tell where a particular user is, ie. Joe is position 100 out of 200.

Ie.

User Score Row
Joe  100    1
Bob  50     2
Bill 10     3

I've seen a few solutions on here but I've tried most of them and none of them actually return the row number.

I have tried this:

SELECT position, username, score
FROM (SELECT @row := @row + 1 AS position, username, score 
       FROM league_girl GROUP BY username ORDER BY score DESC) 

As derived

...but it doesn't seem to return the row position.

Any ideas?

Answer 1

If you are to print the result, why not just add the rank number while looping through the result-set.

Answer 2

You may want to try the following:

SELECT  l.position, 
        l.username, 
        l.score,
        @curRow := @curRow + 1 AS row_number
FROM    league_girl l
JOIN    (SELECT @curRow := 0) r;

The JOIN (SELECT @curRow := 0) part allows the variable initialization without requiring a separate SET command.

Test case:

CREATE TABLE league_girl (position int, username varchar(10), score int);
INSERT INTO league_girl VALUES (1, 'a', 10);
INSERT INTO league_girl VALUES (2, 'b', 25);
INSERT INTO league_girl VALUES (3, 'c', 75);
INSERT INTO league_girl VALUES (4, 'd', 25);
INSERT INTO league_girl VALUES (5, 'e', 55);
INSERT INTO league_girl VALUES (6, 'f', 80);
INSERT INTO league_girl VALUES (7, 'g', 15);

Test query:

SELECT  l.position, 
        l.username, 
        l.score,
        @curRow := @curRow + 1 AS row_number
FROM    league_girl l
JOIN    (SELECT @curRow := 0) r
WHERE   l.score > 50;

Result:

+----------+----------+-------+------------+
| position | username | score | row_number |
+----------+----------+-------+------------+
|        3 | c        |    75 |          1 |
|        5 | e        |    55 |          2 |
|        6 | f        |    80 |          3 |
+----------+----------+-------+------------+
3 rows in set (0.00 sec)

Answer 3

SELECT @i:=@i+1 AS iterator, t.*
FROM tablename t,(SELECT @i:=0) foo