how to initialize List<string> with many string values

Question

have your say your idea or correct the example below please.

List<string> optionList = new List<string>
{
"AdditionalCardPersonAdressType","AdditionalCardPersonSex","AutomaticRaiseCreditLimit","CardDeliveryTimeWeekDay","CardDeliveryTimeWeekEnd","CCAdditionalCardAddress",
"CCAdditionalCardPerson","CCAutoPaidType","CCSendAddressType","CCStatementAddressType","CCStatementAddressType","CCStatementLanguage","CCStatementPeriod",
"CCStatementType","CompanyOwner","CustomerType","EducationStatus","ExchangeAccount","HomeStatus","IsCCAutoPaid","LogoName",
"MaritalStatus","PensionFund","RelationToCardHolder","Sex"}();

Answer 1

Just remove () at the end.

List<string> optionList = new List<string>
            { "AdditionalCardPersonAdressType", /* rest of elements */ };

Answer 2

You could get the values from an external configuration file, an XML file, or a database. The additional advantage is that you can change it without recompilation.

Answer 3

You haven't really asked a question, but the code should be

List<string> optionList = new List<string> { "string1", "string2", ..., "stringN"}; 

i.e. no trailing () after the list.

Answer 4

List<string> mylist = new List<string>(new string[] { "blah, blah, blah" });

I shall refrain from being worried about some of the details in the OP's list... :)