how to loop over the jquery .ajax() success function. i m getting openx banner in loop but success function is not iterating and displaying it only first element of the for loop is displayed. here is the example code: This is in html file:
staticurl='http://d1.openx.org/avw.php?zoneid='
zoneidList=new Array('110904','110903','110905');
for(k=0;k<zoneidList.length;k++)
{
alert(zoneidList[k]);
zoneid=zoneidList[k];
index=k;
$.ajax({
type: "POST",
url:'/ajax/',
data:{"url":zoneid,'index':index} ,
success: function(banner){
alert(banner);
index=k1.split('$$')[1];
alert(index);
$('#flash'+index).append(banner);
}
});
</script>
</head>
<body>
<div id="flash0"></div>
<div id="flash1"></div>
<div id="flash2"></div>
hai
</body>
</html>
please can anyone tell me how to loop over all the zoneids present