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Question

XSLT finding links inside tags in XML documents

Answer 1

A:

This will work right out of the box if you are trying to display this in html format:

<html>
<body>
  <xsl:for-each select="people/person">
     <div>
       <xsl:value-of select="name"/>
     </div>
     <div>
       <xsl:copy-of select="bio"/>
     </div>
  </xsl:for-each>
</body>
</html>

EDIT: changed value-of to copy-of. See this discussion: http://stackoverflow.com/questions/162225/how-do-i-preserve-markup-tags-when-using-xslt

Mikal 2010-06-29 16:20:33

Answer 2

+2 A:

Is there a way to have an xsl stylesheet recognize when a link appears inside a tag in an xml document and turn it into a working link?

Yes. This transformation:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"&gt;
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:template match="/*">
   <table border="1">
     <xsl:apply-templates/>
   </table>
 </xsl:template>

 <xsl:template match="person">
   <tr>
     <xsl:apply-templates/>
   </tr>
 </xsl:template>

 <xsl:template match="person/*">
   <td><xsl:copy-of select="node()"/></td>
 </xsl:template>
</xsl:stylesheet>

when applied on the provided XML document:

<people>
   <person>
      <name>Guy 1</name>
      <bio>Guy 1 is a guy.</bio>
   </person>

   <person>
      <name>Guy 2</name>
      <bio>Guy 2 is from <a href="http://www.example.com"&gt;somewhere&lt;/a&gt;.&lt;/bio&gt;
   </person>
</people>

produces the wanted result:

<table border="1">
   <tr>
      <td>Guy 1</td>
      <td>Guy 1 is a guy.</td>
   </tr>

   <tr>
      <td>Guy 2</td>
      <td>Guy 2 is from <a href="http://www.example.com"&gt;somewhere&lt;/a&gt;.&lt;/td&gt;
   </tr>
</table>

Dimitre Novatchev 2010-06-29 16:44:54

Perfect. This does exactly what I was looking for.

Skunkwaffle 2010-06-29 18:11:56

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XSLT finding links inside tags in XML documents

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