i have such code
var menu = _dataManager.Menu.Details(id);
var menu2 = _dataManager.Menu.Details(id);
menu.Name = "AAA";
in this case menu2.Name will be "AAA", i guess it because of reference, but how can i solve it?
views:
23answers:
2
A:
Entity lazy loads data. Force the load and disconnect it from the Model and then it will not be AAA.
Eager load:
DataLoadOptions op = new DataLoadOptions();
op.LoadWith<Details>(x => x.Menu);
//etc...
_dataManager.LoadOptions = op;
Update: It appears that in the past I disconnect by copying the data out to a non-entity POCO.
Russell Steen
2010-07-01 15:10:24
any code sample?
kusanagi
2010-07-01 15:12:29
yeah, trying to find the code for the last time i did this. reading any property should force the load. Disconnecting is more specific.
Russell Steen
2010-07-01 15:14:55
Good answer Russell. It got me searching for a way to force an Enumeration on IEnumerable objects. I'm looking now but I dont think there's an Enumerate() method or anything. Would be nice in this context.
Jamie Dixon
2010-07-01 15:16:01
A:
Most likely the Details method is set to return a single instance of the menu item regardless of how many times you put it into different variable names.
One solution would be to use a different dataManager object for the second menu item.
Jamie Dixon
2010-07-01 15:10:49