Allow literal . in regular expression

Question

^[a-zA-Z]:{1}/(\w+/)+$

I want to allow . as well in the expression in \w+. How can I do this?

Answer 1

\. should do it. You don't need the escaping \ if you put it in a character class. For your exact example:

^[a-zA-Z]:{1}/([\w.]+/)+$

Answer 2

The . is a special character in regular expression syntax, so you have to escape it with a backslash. \.

Answer 3

Replace

(\w+/)

with

([\w.]+/)

Answer 4

The expression should be ^[a-zA-Z]:/(\w+./)+$ or ^[a-zA-Z]:/([\w.]+/)+$