You need to do:
public class EnumerableDisposer<T, J> : IDisposable
where T : IEnumerable<J> where J : IDisposable
{
// Implement...
Unfortunately, in order to wrap any internal type (IEnumerable<J>
, in your code), your "wrapping" class needs to have the type J
defined in the generic definition. In addition, in order to add the IEnumerable<J>
constraint, you need to have the other type T
.
That being said, if you want to avoid the double generic type specification, you could always rework this as follows:
public class EnumerableDisposer<T> : IDisposable
where T : IDisposable
{
public EnumerableDisposer(IEnumerable<T> enumerable)
{
// ...
This forces you to construct it with an IEnumerable<T>
where T is IDisposable, with a single generic type. Since you're effectively adding the IEnumerable<T>
constraint via the constructor, this will function as well as the previous option. The only downside is that you need to have the generic done at construction time, but given the name, I suspect this will be fine...