How to escape Unicode escapes in Groovy's /pattern/ syntax

Question

The following Groovy commands illustrate my problem.

First of all, this works (as seen on lotrepls.appspot.com) as expected (note that \u0061 is 'a').

>>> print "a".matches(/\u0061/)

true

Now let's say that we want to match \n, using the Unicode escape \u000A. The following, using "pattern" as a string, behaves as expected:

>>> print "\n".matches("\u000A");

Interpreter exception: com.google.lotrepls.shared.InterpreterException:
org.codehaus.groovy.control.MultipleCompilationErrorsException: startup failed,
Script1.groovy: 1: expecting anything but ''\n''; got it anyway
@ line 1, column 21. 1 error

This is expected because in Java at least, Unicode escapes are processed early (JLS 3.3), so:

print "\n".matches("\u000A")

really is the same as:

print "\n".matches("
")

The fix is to escape the Unicode escape, and let the regex engine process it, as follows:

>>> print "\n".matches("\\u000A")

true

Now here's the question part: how can we get this to work with the Groovy /pattern/ syntax instead of using string literal?

Here are some failed attempts:

>>> print "\n".matches(/\u000A/)

Interpreter exception: com.google.lotrepls.shared.InterpreterException:
org.codehaus.groovy.control.MultipleCompilationErrorsException: startup failed,
Script1.groovy: 1: expecting EOF, found '(' @ line 1, column 19.
1 error

>>> print "\n".matches(/\\u000A/)

false

>>> print "\\u000A".matches(/\\u000A/);

true

Answer 1

~"[\u0000-\u0008\u000B\u000C\u000E-\u001F\u007F-\u009F]"

Appears to be working as it should. According to the docs I've seen, the double backslashes shouldn't be required with a slashy string, so I don't know why the compiler's not happy with them.