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Answer 1

+6 A:

You must quote +:

$get('msgBar').replace(/\+/g,' ');

'+' is a meta character, like '*'. It means "one more repetitions". It you literally want '+' , then you have to quote it with the backslash.

Luther Blissett 2010-07-14 16:10:53

Specifically, you must quote it because '+' has meaning in regular expressions, and the first argument to replace is used as a regex, not a bare string for comparison...

Tetsujin no Oni 2010-07-14 16:13:28

Unfortunately, I've already tried that (as in the original post), and it didn't work for whatever reason... that is, only the first + is replaced.

Julian H. Lam 2010-07-14 16:13:54

No you didn't. You forgot the 'g' - it means "global match" and instructs regex to find and replace **all** matches.

Luther Blissett 2010-07-14 16:16:52

T'was a typo. I copied and pasted your solution and it did not work. Sorry.

Julian H. Lam 2010-07-14 16:18:33

@Luther's answer works for me. *Edit:* On second thought, -deletes my answer-

BoltClock 2010-07-14 16:21:19

@Julian it definitely works. You must have some other problem; post more of your code.

Pointy 2010-07-14 16:25:10

... yep, it works. My apologies.I was editing the wrong block of code. Fail.

Julian H. Lam 2010-07-14 16:28:28

Pointy - $get's pretty cool, actually. It's a mootools extension written by Jens Anders Bakke.Take a look: http://webfreak.no/wp/2007/09/05/get-for-mootools-a-way-to-read-get-variables-with-javascript-in-mootools/

Julian H. Lam 2010-07-14 16:29:13

@Julian - MooTools provides string extensions to deal with [querystrings](http://mootools.net/docs/more/Native/String.QueryString#String:parseQueryString). You could parse the querystring as `location.search.substr(1).parseQueryString().msgBar`. Looks a little verbose, but a wrapper function like `$get` is easy to write for the above.

Anurag 2010-07-14 16:47:51

Thanks, Anurag - looks great! That might be a better solution to use in conjunction with $get

Julian H. Lam 2010-07-15 19:26:35

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