identify smallest integer and number of times it was entered

Question

How can i write the code to identify the smallest integer i entered and how many times it appeared in the list i key in? Can somebody please help?

#include<stdio.h>
#define constant-999

int main()
{
 int num, count;

 printf("Enter a list of integers (-999 to stop) : ");
 while(scanf("%d", &num) != -999)

Answer 1

Expand the while() loop to monitor this:

#define _WIN32_WINNT 0x0400
#define WIN32_LEAN_AND_MEAN
#include <windows.h>

#include <stdio.h>
#include <conio.h>

void main()
{
    int num = 0;
    int smallest = 12345;
    int smallest_count = 0;
    printf("Enter a list of integers (-999 to stop) : ");
    while(scanf("%d", &num) != -999)
    {
        if(num < smallest)
        {
            smallest = num;
            smallest_count = 1;
        }
        else if(num == smallest)
        {
            smallest_count++;
        }
    }
}

Answer 2

I agree with Steven's comment but as a hint, since you need to count occurrences you'll need to iterate through the entire thing anyway.

Answer 3

With a text editor.

Notepad++ is quite nice, but really anything will do.

Answer 4

A simple solution is to declare an array of numeric counts and using the number read as the index. You may have to offset the index if you deal with negative numbers:

unsigned int number_counts[1000] = {0};

//...

number_counts[num]++;

// or 
number_counts[num + 500]++;

If you are using a linked list, add a count field and increment that.