Can I insert one variable into other variable in Xsl? Thanks

Question

<xsl:variable name="id">
  <idNum>0607V45621014F</idNum>
</xsl:variable> 

<xsl:variable name="pathId" select="Orders/Order[ORD_Num='$id/idNum']"/>

....not select the idNum

an other..not..

<xsl:variable name="XmlFile" select="YG.xml"/>
<xsl:value-of select="document($XmlFile)/aziende/azienda/ragione_sociale"/>

or other...not..

<xsl:variable name="tagName" select="aziende"/>
<xsl:value-of select="document($XmlFile)/$tagName/azienda/ragione_sociale"/>

help me!

Thank bye GB

Answer 1

1)

<xsl:variable name="pathId" select="Orders/Order[ORD_Num='$id/idNum']"/> 

You are saying: An Order element wich has at least one ORD_Num child with string value equal to '$id/idNum'.

Replace with:

<xsl:variable name="pathId" select="Orders/Order[ORD_Num=$id]"/> 

Because the string value of $id variable (a Result Tree Fragment as you define) is 0607V45621014F.

Note: It would be better if you define $id as a string like select="'0607V45621014F'". Also, you can't (in XSLT 1.0) do: [ORD_Num=$id/idNum] because / operator can't be apply to a RTF.

2)

<xsl:variable name="XmlFile" select="YG.xml"/>   
<xsl:value-of select="document($XmlFile)/aziende/azienda/ragione_sociale"/> 

Here, you are saying: Let be $XmlFile a node set with all YG.xml elements childs of context node, etc.

Replace (if you want a document with relative uri YG.xml)

<xsl:variable name="XmlFile" select="'YG.xml'"/>   

Note: this does not trought an error because document() is very versatile (It's the few ones that take an object as param)

3)

<xsl:variable name="tagName" select="aziende"/>                             
<xsl:value-of select="document($XmlFile)/$tagName/azienda/ragione_sociale"/>

This does not work because the right expresion of / must be a path (In XSLT 2.0 can be a function as well).

Replace with:

<xsl:variable name="tagName" select="document($XmlFile)/aziende"/>                             
<xsl:value-of select="$tagName/azienda/ragione_sociale"/>

Or

<xsl:variable name="tagName" select="'aziende'"/>                             
<xsl:value-of select="document($XmlFile)/*[name()=$tagName]/azienda/ragione_sociale"/>