ansaurus

Question

Answer 1

+3 A:

This stylesheet:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"&gt;
    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>
    <xsl:template match="Hierarchy[position() != 1]"/>
    <xsl:template match="Hierarchy[1]">
        <xsl:apply-templates select="." mode="Hierarchy"/>
    </xsl:template>
    <xsl:template match="Hierarchy" mode="Hierarchy">
        <xsl:copy>
            <xsl:apply-templates select="@*"/>
            <xsl:apply-templates select="following-sibling::Hierarchy[1]" mode="Hierarchy"/>
        </xsl:copy>
    </xsl:template>
</xsl:stylesheet>

Result:

<root>
    <Element1>
        <Hierarchy attr="value">
            <Hierarchy attr="value">
                <Hierarchy attr="value">
                    <Hierarchy attr="value"></Hierarchy>
                </Hierarchy>
            </Hierarchy>
        </Hierarchy>
    </Element1>
    <AnotherElement>
        <YetAnotherElement>
            <Hierarchy attr="value">
                <Hierarchy attr="value">
                    <Hierarchy attr="value">
                        <Hierarchy attr="value"></Hierarchy>
                    </Hierarchy>
                </Hierarchy>
            </Hierarchy>
        </YetAnotherElement>
    </AnotherElement>
</root>

Alejandro 2010-07-20 13:20:32

+1 for the perfect solution and for being faster than me :)

Dimitre Novatchev 2010-07-20 13:26:11

@Dimitre: +1. That really is an achievement, ja!

Alejandro 2010-07-20 17:08:30

Answer 2

A:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"&gt;
  <xsl:output method="xml" indent="yes"/>

  <xsl:strip-space elements="*" />

  <xsl:template match="@* | node()">
    <xsl:if test="name() != 'Hierarchy'">
      <xsl:copy>
        <xsl:apply-templates select="@* | node()"/>
      </xsl:copy>
    </xsl:if>
  </xsl:template>

  <xsl:template match="Hierarchy">
    <xsl:if test="position() = 1">
      <xsl:call-template name="makeTree">
        <xsl:with-param name="elem" select="." />
      </xsl:call-template>
    </xsl:if>
  </xsl:template>

  <xsl:template name="makeTree">
    <xsl:param name="elem" />
    <xsl:copy>
      <xsl:apply-templates select="$elem/@*" />
      <xsl:if test="count($elem/following-sibling::node()) > 0">
        <xsl:call-template name="makeTree">
          <xsl:with-param name="elem" select="$elem/following-sibling::node()[1]" />
        </xsl:call-template>
      </xsl:if>
    </xsl:copy>
  </xsl:template>
</xsl:stylesheet>

svick 2010-07-20 13:45:42

ansaurus

tags:

views:

answers:

How to convert flat list to the tree

related questions