Firstly: the question (and some of the other answers) seem to be based on the faulty premise that C is a strict subset of C++, which is not in fact the case. Compiling C as C++ is not the same as compiling it as C: it can change the meaning of your program!
C will mostly compile as C++, and will mostly give the same results, but there are some things that are explicitly defined to give different behaviour.
Here's a simple example - if this is your a.c
:
#include <stdio.h>
int main(void)
{
printf("%d\n", sizeof('x'));
return 0;
}
then compiling as C will give one result:
$ gcc a.c
$ ./a.out
4
and compiling as C++ will give a different result (unless you're using an unusual platform where int
and char
are the same size):
$ g++ a.c
$ ./a.out
1
because the C specification defines a character literal to have type int
, and the C++ specification defines it to have type char
.
Secondly: gcc
and g++
are not "the same compiler". The same back end code is used, but the C and C++ front ends are different pieces of code (gcc/c-*.c
and gcc/cp/*.c
in the gcc source).
Even if you stick to the parts of the language that are defined to do the same thing, there is no guarantee that the C++ front end will parse the code in exactly the same way as the C front end (i.e. giving exactly the same input to the back end), and hence no guarantee that the generated code will be identical. So it is certainly possible that one might happen to generate faster code than the other in some cases - although I would imagine that you'd need complex code to have any chance of finding a difference, as most of the optimisation and code generation magic happens in the common back end of the compiler; and the difference could be either way round.