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Answer 1

+4 A:

I would use regex here

var sid = []
var matches = "ctl00_ctl00_cphBody_bodycph_content_rdo_SID_25_SortOrder_17".match(/_SID_(\d+)/);
if(matches) sid.push(parseInt(matches[1]));

Anpher 2010-07-22 07:19:09

@Anpher: Could you please provide more details on how would it get me the digit in array ?

Shantanu Gupta 2010-07-22 07:20:34

The "(\d+)" part in regex is considered to accept only digits

nemke 2010-07-22 07:25:13

I would add an `assert( matches.count == 1 )`.

xtofl 2010-07-22 07:32:52

@anpher. you're ignoring the requirement to go through the array and output an array.

Ben 2010-07-22 07:33:14

Answer 2

+7 A:

use jquery map + regexp

var arr= ['tl00_ctl00_cphBody_bodycph_content_rdo_SID_25_SortOrder_17',
    'ctl00_ctl00_cphBody_bodycph_content_rdo_SID_26_SortOrder_18',
    'ctl00_ctl00_cphBody_bodycph_content_rdo_SID_27_SortOrder_19']

    var out = $(arr).map(function(){
        return this.match(/SID_(.*?)_/)[1];
    });

out should be an array of the values..

(assuming all the values in the array do match the pattern)

Ben 2010-07-22 07:23:26

@Ben: why you used `[1]` in `this.match(/SID_(.*?)_/)[1]`. What task does it accomplish.

Shantanu Gupta 2010-07-22 07:28:34

@Shantanu. match returns an array, with the first item (0) the whole matched expression and the second (1) the first capture group, ie. the (.*?) expression.Try adding console.log(this.match(/SID_(.*?)_/)) before the return and run it in firefox+firebug to see the results of the match function

Ben 2010-07-22 07:32:05

Especially like the usage of `map` to obtain a transformed array.

xtofl 2010-07-22 07:35:09

I deleted my answer, I wrote it on my iPhone so I couldn't be as descriptive as I wanted to be, but the reason I used `this.split("_")[6]` instead is that it is much more readable and requires no knowledge of regular expressions.

Andy E 2010-07-22 07:36:41

@Andy. True. But I assume all that crazy string construction comes from using asp.net controls (right?). If the control is moved elsewhere or nested in or out of another, the number of _ will change and the index won't work anymore..

Ben 2010-07-22 07:39:53

@Ben: you should add `.get()` at the end of `.map()` to return a true array. Updated that.

jAndy 2010-07-22 07:42:26

@Ben: hmm I didn't think about that - good point. +1 to your answer :-)

Andy E 2010-07-22 07:42:51

Don't use `$.fn.map` for regular arrays... use `$.map`, and then you won't have to fuss with `.get()`...

J-P 2010-07-22 08:10:37

Ben 2010-07-22 10:22:08

Answer 3

A:

This solution is totally reliant on the overall string form not changing too much, ie the number of "underscores" not changing which seems fragile, props given to commenter below but he had the index wrong. My original solution first split on "SID_" since that seemed more like a key that would always be present in the string going forward.

Given:

s = "ctl00_ctl00_cphBody_bodycph_content_rdo_SID_25344_SortOrder_17"

old solution:

array.push(parseInt(s.split("SID_")[1].split("_")[0]))

new solution

array.push(parseInt(s.split("_")[7])

nicholasklick 2010-07-22 07:24:58

Nice, except that it works for 2-digit numbers only.

xtofl 2010-07-22 07:34:29

why not just `s.split("_")[6]`?

Andy E 2010-07-22 07:37:29

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How to manipulate string in an array

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