Hello,
I have a website coded with XML+XSLT that outputs me a full HTML website. Now, to make the site more dinamic I want to split some parts of the document: the header, footer and sidebar. I was looking at Google and I found this solution:
<xsl:param name="doc" select="document('menu.xml')"/>
<xsl:template match="/">
<html><head></head><body><xsl:for-each
select="$doc"><xsl:apply-templates/></xsl:for-each></body></html>
</xsl:template>
I was trying to apply it and I can get it working. This is the way I am using:
I changed the route to "../menu.xml" becasuse the xsl is inside a folder, this works well.
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="menu" select="document('../menu.xml')"/>
<xsl:template match="/">
more valid and working code and then:
<ul class="menu_top">
<xsl:for-each select="$menu">
<li>
<a>
<xsl:attribute name="href">
#<xsl:value-of select="link" />
</xsl:attribute>
<xsl:value-of select="name"/>
</a>
</li>
</xsl:for-each>
</ul>
<xsl:for-each select="$menu">
<div class="submenu">
<xsl:attribute name="id">
<xsl:value-of select="link" />
</xsl:attribute>
<ul>
<xsl:for-each select="child">
<li>
<a>
<xsl:attribute name="href">
<xsl:value-of select="link" />
</xsl:attribute>
<xsl:value-of select="name"/>
</a>
</li>
</xsl:for-each>
</ul>
</div>
</xsl:for-each>
Finally my menu.xml:
<?xml version="1.0" encoding="utf-8"?>
<menu>
<category>
<name>First</name>
<link>menu-1</link>
<child>
<name>Child 1</name>
<link>#</link>
</child>
<child>
<name>Child 2</name>
<link>#</link>
</child>
</category>
</menu>
I've more categories entries but I simplified it.
Thanks in advance!