Compact LINQ syntax for float ranges?

Question

Is there a compact, built-in way to generate a range of floats from min to max with a given step?

E.g.: range(10, 20, 0.1) [but built-in].

Answer 1

No, there's nothing built in. It would be really easy to write your static method though. Something like:

public static IEnumerable<float> FloatRange(float min, float max, float step)
{
    for (float value = min; value <= max; value += step)
    {
        yield return value;
    }
}

EDIT: An alternative using multiplication, as suggested in comments:

public static IEnumerable<float> FloatRange(float min, float max, float step)
{
    for (int i = 0; i < int.MaxValue; i++)
    {
        float value = min + step * i;
        if (value > max)
        {
            break;
        }
        yield return value;
    }
}

In MiscUtil I have some range code which does funky stuff thanks to Marc Gravell's generic operator stuff, allowing you:

foreach (float x in 10f.To(20f).Step(0.1f))
{
    ...
}

Answer 2

You could do

Enumerable.Range(100, 100).Select(i => i / 10F)

But it isn't very descriptive.