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Answer 1

+3 A:

Assuming the .parent() part is correct, try this:

var result = $j(this).parent().contents().last().text();

You may want to trim the result, because there will likely be white space.

var result = $j(this).parent().contents().last().text();

result = $j.trim(result);

Or if there isn't any other text, you can just do this:

var result = $j(this).parent().text();

patrick dw 2010-07-30 22:57:04

Works with a tweak: `var result = $j(this).parent().contents().last().text();` (http://jsfiddle.net/krLw3/)

Pat 2010-07-30 22:59:56

You're right, it works fine

Bohdan Pohorilets 2010-07-30 23:02:07

@Pat - Thanks. :o) I caught that before my last edit. In my test code I had `.text()` on the next line.

patrick dw 2010-07-30 23:02:23

Answer 2

A:

($j(this).parent().html().substring(78, $j(this).parent().html().length)

Any better solutions ?

Bohdan Pohorilets 2010-07-30 22:57:19

Answer 3

+1 A:

Try the following to get 'All'

obj = $(this).parent().get(0); 
var allText = obj.lastChild.nodeValue;

andreas 2010-07-30 23:15:06

andreas - Good solution. Although if you're going to take the native API route, might as well go all the way: `var allText = this.parentNode.lastChild.nodeValue;` :o)

patrick dw 2010-07-30 23:22:42

i admit it...it's a 'hybrid' :) Good point there Patrick

andreas 2010-07-31 10:49:56

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how to get part of html in javascript?

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