I have a tree expression that looks like this:
.Block(
System.Object $instance,
MyType2 $result) {
$result = (MyType2)((MyType1)$instance).Property1;
.Goto return { };
.Label
.LabelTarget useDefault:;
$result = .Default(MyType2);
.Label
.LabelTarget return:;
$result
}
These are the custom types that are used in the expression tree:
public class MyType1
{
public MyType2 Property1 { get; set; }
}
public class MyType2
{
}
Finally, this is how I build, compile and invoke the expression tree (this won't run exactly like this because I've left out some code to simplify things):
object instance = new MyType1();
Expression expression = ... // n => n.Property1
ParameterExpression instanceParameter = Expression.Variable(
typeof(object), "instance");
ParameterExpression resultVariable = Expression.Variable(
typeof(MyType2), "result");
LabelTarget useDefaultLabel = Expression.Label("useDefault");
LabelTarget returnLabel = Expression.Label("return");
List<Expression> targetFragments = new List<Expression>();
MemberInfo memberInfo = (MemberInfo)expression.Body.Member;
MemberExpression member = ConstantExpression.MakeMemberAccess(
Expression.Convert(instanceParameter, memberInfo.DeclaringType),
memberInfo);
targetFragments.Add(
Expression.Assign(
resultVariable,
Expression.Convert(member, typeof(MyType2))));
targetFragments.Add(Expression.Goto(returnLabel));
targetFragments.Add(Expression.Label(useDefaultLabel));
targetFragments.Add(Expression.Assign(resultVariable,
Expression.Default(typeof(MyType2))));
targetFragments.Add(Expression.Label(returnLabel));
targetFragments.Add(resultVariable);
Expression finalExpression = Expression.Block(
new[] { instanceParameter, resultVariable },
targetFragments);
ParameterExpression parameter = Expression.Variable(typeof(object));
MyType2 result = Expression.Lambda<Func<T, MyType2>>(expression, parameter)
.Compile()(instance);
The invoke throws the following exception however:
Object reference not set to an instance of an object. at lambda_method(Closure , Object )
I think this is happening because of the $result = (MyType2)((MyType1)$instance).Property1;
assignment but I don't understand why because the instance that is passed to the expression isn't null
.